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Post by Youngy on Aug 23, 2013 19:40:34 GMT
Grindsted = 50
1. Michael Jepsen Jensen - 3, 3, 2, 2, 2, 3 = 15 2. Kacper Gomolski - 1, 3, 3, 2, 3, 2 = 14 3. Szymon Wozniak - 3, 2, 1, 1, 1, 3 = 11 4. Johannes Kikkenborg - 1, 0, 1, 2, 2, 1 = 7 5. Claus Lauridsen - 2, R, 1, F = 3
Holstebro = 37
1. Bjarne Pedersen - 2, R, 2, 3, 1, 6^, R = 14 2. Ronnie Jamrozy - 0, 1, 1, R, 0, 2 = 4 3. Andriej Karpov - 2, 1, 3, 3 = 9 4. Jonas B. Andersen - 0, 2, 0, 3, 3, 1, 1 = 10 5. Mikkel B. Andersen - 0, R, 0, 0 = 0
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